2^(3x+2)=1/16

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Solution for 2^(3x+2)=1/16 equation: 



2^(3x+2)=1/16

We move all terms to the left:

2^(3x+2)-(1/16)=0

We add all the numbers together, and all the variables

2^(3x+2)-(+1/16)=0

We get rid of parentheses

2^(3x+2)-1/16=0

We multiply all the terms by the denominator


(2^(3x+2))*16-1=0

We move all terms containing x to the left, all other terms to the right

(2^(3x+2))*16=1

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